Question

when a denominater of (1/2√5) is rationalized, it becomes(√k/10), find k.​

Answer 1

Answer:

k= √5

Step-by-step explanation:

rationalising

= 1/2√5*2√5/2√5

= 2√5/4*5

solving we get

= √5/10

Answer 2

Step-by-step explanation:

$\frac{1}{2 \sqrt{5} } = \frac{1 \times 2 \sqrt{5} }{2 \sqrt{5} \times 2 \sqrt{5} } \\ = \frac{2 \sqrt{5} }{4 \times 5} \\ = \frac{ \sqrt{5} }{2 \times 5 } \\ = \frac{ \sqrt{5} }{10} \\ thus \: \\ \frac{ \sqrt{k} }{10} = \frac{ \sqrt{5} }{10} \\ \sqrt{k} = \sqrt{10 } \\ k = 5 \: \: \: \: \: \: ans$