Question

when a denominater of (1/2√5) is rationalized, it becomes(√k/10), find k.​

Answer 1

Answer:

I think the answer is root 2

Answer 2

Answer:

$1 \\ - \\ 2 \sqrt{5}$

we need to multiply the numerator and denominator with 2√5

WE GET

$2 \sqrt{5} \\ - \\ (2 \sqrt{5) {}^{2} }$

(2√5)=2^2 * (√5)^2 = 4*5 = 20

WE GET

$2 \sqrt{5} \\ - \\ 20$

as we need the denominator to be 10 we can do cancellation. Then we get

$\sqrt{5} \\ - \\ 10$

so K is √5