Math, asked by PopoKopo, 3 months ago

When a die is thrown, find the probability of an event of getting :
(a) a prime number
(b) not a prime number
(c) a number greater than 5
(d) a number not greater than 5

I will mark brainliest who gives first and correct answer with explanation

Answers

Answered by lovinglavisha
20

Probability of getting prime numbers:-

Total number of prime numbers =2,3,5

Total numbers in die=6

Probability =possible outcomes /total number of outcomes.

3/6=1/2

Probability of getting a number which is not prime numbers:-

Total numbers which are not prime number=4,6

Total numbers in a die =6

Probability =Possible outcome / total number of outcomes

2/6=1/3

a number greater than 5 :-

A number which is greater than 5=6

Total numbers in a die

Probability =possible outcomes / total numbers of outcomes

1/6

a number not greater than 5:-

numbers which are not greater than 5=1,2,3,4,5

Total numbers in a die =6

Probability =Possible outcome / total number of outcomes

5/6

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Answered by Anonymous
25

Answer:

your answer is above in the image

Step-by-step explanation:

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