Question

When a die is thrown list the outcomes of an event of getting A. prime number
B. not a prime number
C. a number not greater than 5.

Answer 1

outcomes of a die thrown = 1,2,3,4,5,6

Total number of outcomes after throwing die=6

(A) getting a prime number

prime numbers in die =2, 3,5

no. of prime numbers outcomes = 3

probability (prime number) =

$= \frac{no.of \: prime \: outcomes}{total \: no. \: of \: outcomes}$

$= \frac{3}{6}$

$= \frac{1}{2}$

therefore probability of getting a prime number after throwing a die is ½

(B)

getting a non prime number

non prime numbers in die = 4,6

no. of non prime numbers outcomes = 2

probability (prime number) =

$= \frac{no.of \: non \: prime \: outcomes}{total \: no. \: of \: outcomes}$

$= \frac{2}{6}$

$= \frac{1}{3}$

so, the probability of getting a non prime number after throwing a die is ⅓.

(C) for getting a number not greater than 5

smaller numbers than 5 in a die = 1,2,3,4

no. of outcomes ofnumber not greater than 5 = 4

probability ( number not greater than 5)

$= \frac{no.of \:outcome \: of \: no. \: greater \: than \: 5 \: }{total \: no.\: of \: outcomes}$

$= \frac{4}{6}$

$= \frac{2}{6}$

so, the probability of getting a number not greater than 5 after throwing a die is 2/6