Question

when a die is thrown once find the probability of getting. even prime number,odd number,factors of 6​

Answer 1

Total Number of Outcomes = 6

1. Getting an even prime number for certain event (A) = 1 ( No. is 2)

Therefore p(A) = 1/6

2. Getting a odd number for a certain event (B) = 3 (No. are 1, 3, and 5)

Therefore p(B) = 3/6 = 1/2

3. Getting a number which is factor of 6 for a certain event (C) = 1 ( No. is 6 only)

Therefore p(C) = 1/6

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