Math, asked by barath86296, 4 months ago

when a die is thrown what is the probability of getting (a) a prime number (b) not a prime number​

Answers

Answered by successfulshyam11
2

Answer:

+50 v+50vvv h

Step-by-step explanation:

Answered by ravi2303kumar
1

Answer:

a.  (1/2)

b.  (1/2)

Step-by-step explanation:

When a die is thrown,

S = {1,2,3,4,5,6}

=> n(S) = 6

let A be the event of getting a prime number while throwing a die.

=> A = {2,3,5}

=> n(A) = 3

=> p(A) = n(A)/n(S) = 3/6 = 1/2

let B be the event of not getting a prime number while throwing a die.

=> B = {1,4,6}

=> n(B) = 3

=> p(B) = n(B)/n(S) = 3/6 = 1/2

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