when a die is thrown what is the probability of getting (a) a prime number (b) not a prime number
Answers
Answered by
2
Answer:
+50 v+50vvv h
Step-by-step explanation:
Answered by
1
Answer:
a. (1/2)
b. (1/2)
Step-by-step explanation:
When a die is thrown,
S = {1,2,3,4,5,6}
=> n(S) = 6
let A be the event of getting a prime number while throwing a die.
=> A = {2,3,5}
=> n(A) = 3
=> p(A) = n(A)/n(S) = 3/6 = 1/2
let B be the event of not getting a prime number while throwing a die.
=> B = {1,4,6}
=> n(B) = 3
=> p(B) = n(B)/n(S) = 3/6 = 1/2
Similar questions