Question

When a dielectric material is introduced between the plates of a parallel plate capacitor what happens to its capacitence

Answer 1

Explanation:

When dielectric material (k) introduce between the plate of parallel capacitor then Capacitance increase k time the initial capacitance.

Means

suppose that without dielectric the capacitance of capacitor is C°.

Then when dielectric insert between plate then the value of new Capacitance is

C =C°K.

Let us prove this by simple method:

We know :

C =Q / ∆V

if the capacitance without dielectric:

C° = Q /V°....i

Note : C° I consider it Cnot and V° as Vnot

Capacitance with dielectric

C =Q /V .....ii

We know The potential of capacitance with dielectric is :

V = V° /K

So putting the value of V in ii equation

We get :

C = Q K /V°

and Q /V° = C° By i equation

So. C = C°K .

Thank you

Answer 2

When a dielectric material is introduced between the plates of a parallel plate capacitor its capacitance becomes 'zero' :

• When a nonconductor material is introduced between the plates of a charged condenser.
• It becomes polarized (its internal + and - charges slightly separate) by the electrical field obligatory by the fees already on the condenser plates.
• This polarization within the dielectric material sets up its field of force that opposes the prevailing field.
• A part neutralizing it, allowing a lot of (additional) charges to behold on on the plates for constant voltage.
• Capacitance is therefore hyperbolic. C = q / V