When a fair die is thrown twice, what is the probability of scoring first 1 then 2
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3
Answer:
When a fair die is thrown twice then the probability of scoring (1,2) is = 1/36
Step-by-step explanation:
The number of possible outcomes are:-
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
out of these 36 outcomes only one outcome is present
So,
Probability of scoring (1,2) is = P(E)/P(S)
= 1/37
Answered by
1
37 is the answer
hope it helps you
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