Question

When a force (3.2.1) N acts on the body displacement of the body in the direction of y-axis is 5 m.calculate work done​

Answer 1

Answer:

The work done is 10 J

Explanation:

Force, $\overline{F}=\left( 3,2,1\right) N=3\widehat{i}+2\widehat{j}+1\widehat{k}N$

Displacement, $\overline{S}=0\widehat{i}+5\widehat{j}+0\widehat{k}m$

We know that,

             Work done  $W=\overline{F}\cdot \overline{S}$

                    $\begin{aligned}W=3\times 0+2\times 5+1\times 0\\=10 J\end{aligned}$