Question

When a force is applied a body of mass 5 kg is accelerated by 20 m/s-2.
What is the force applied?

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Answer 1

Answer:

We work this solution along the 2 axes.

For x - axis

u=6, t=10sec, v=0 If a be the acceleration of the particle.

Using Newton's equation of motion, v=u+at

0=6+10a Thus, a =

5

−3

Similarly along the y axis

u=−2, v=6, t=10. IfA be the acceleration

6=−2+10A,A=0.8

Now, Using, Newton's second law,

F=ma

F

=m

a

F

=5×(−0.6i+0.8j)

F

=−3i+4j

Explanation:

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