Question

when a force is applied on 2kg and 4kg masses one after another ,the acceleration produced on them are 2m/s^2 and 1m/s^2 respectively.What is the magnitude of that force?

Answer 1

ProvidEd that:

$\sf Case \: first \begin{cases} & \sf{Mass \: of \: body= \bf{2 \: kg}} \\ \\ & \sf{Acceleration \: produced \: = \bf{2 \: ms^{-2}}} \end{cases}$

$\sf Case \: second \begin{cases} & \sf{Mass \: of \: body= \bf{4 \: kg}} \\ \\ & \sf{Acceleration \: produced \: = \bf{1 \: ms^{-2}}} \end{cases}$

To calculaTe:

• The force in case 1st
• The force in case 2nd

SoluTion:

• The force in case 1st = 4 N
• The force in case 2nd = 4 N

UsiNg concept:

• Newton second law of motion that tell us about the formula to find the force.

UsiNg formula:

• ${\small{\underline{\boxed{\pmb{\sf{F \: = ma}}}}}}$

Where, a denotes acceleration, F denotes force and m denotes mass.

RequirEd solution:

★ In the case first!

$:\implies \sf Force \: = Mass \times Acceleration \\ \\ :\implies \sf F \: = m \times a \\ \\ :\implies \sf F \: = ma \\ \\ :\implies \sf F \: = 2(2) \\ \\ :\implies \sf F \: = 4 \: Newton \\ \\ :\implies \sf Force \: = 4 \: Newton$

Therefore, 4 Newton is the magnitude of force in case first!

★ In the case second!

$:\implies \sf Force \: = Mass \times Acceleration \\ \\ :\implies \sf F \: = m \times a \\ \\ :\implies \sf F \: = ma \\ \\ :\implies \sf F \: = 4(1) \\ \\ :\implies \sf F \: = 4 \: Newton \\ \\ :\implies \sf Force \: = 4 \: Newton$

Therefore, 4 Newton again is the magnitude of force in case second!

Answer 2

Answer:3N is the best answer

Explanation: