Question

when a force is applied on a body of mass 10 kg for a period of 4s the velocity of the body changes from 6m/s to 8m/s.
what is initial momentum,final momentum,change of momentum force applied,impulse experienced and the relation between impulse and change in momentum?

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The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s.

a) what is the momentum before the force acts?

b) What is the momentum after the force acts?

c) what is the gain momentum per second?

d) What is the value of the force?

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Answer

Mass of the body =10 kg

Initial velocity u=4 m/s

Final velocity v=8 m/s

Time t=2s

a) Momentum before force acts p

1

=m×u=10×4=40kg.m/s

b) Momentum after force acts p

2

=m×v=10×8=80kg.m/s

c) Gain in momentum per second =

2

40

=20kg.m/s

d) Acceleration a=

t

v−u

=

2

8−4

=2m/s

2

Force =m×a=10×2=20 N