Question

When a force is applied on a body of mass 10 kg for a period of 4 s, the velocity of the body changes from 6 m/s to 8 m/s.
a) What is the initial momentum of the body?
b) What is the final momentum of the body?
c) What is the change of momentum of the body?
d) What is the rate of change of momentum of the body?
e) What is the force applied on the body?
f)What is the impulse experienced by the body?
g)What is the relation between impulse and change in momentum?​

Answer 1

Explanation:

Mass of the body =10 kg

Initial velocity u=4 m/s

Final velocity v=8 m/s

Time t=2s

a) Momentum before force acts p

1

=m×u=10×4=40kg.m/s

b) Momentum after force acts p

2

=m×v=10×8=80kg.m/s

c) Gain in momentum per second =

2

40

=20kg.m/s

d) Acceleration a=

t

v−u

=

2

8−4

=2m/s

2

Force =m×a=10×2=20 N

Answer 2

Answer:

hope it helps you my dear friend OK bye