when a force is applied on a body of mass 10 kg for a period of 4s the velocity of the body changes from 6m/s to 8m/s
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4
Answer:
Mass of the body =10 kg
Initial velocity u=4 m/s
Final velocity v=8 m/s
Time t=2s
a) Momentum before force acts p
1
=m×u=10×4=40kg.m/s
b) Momentum after force acts p
2
=m×v=10×8=80kg.m/s
c) Gain in momentum per second =
2
40
=20kg.m/s
d) Acceleration a=
t
v−u
=
2
8−4
=2m/s
2
Force =m×a=10×2=20 N
Answered by
4
Mass of the body =10 kg
Initial velocity u=4 m/s
Final velocity v=8 m/s
Time t=2s
a) Momentum before force acts p
1
=m×u=10×4=40kg.m/s
b) Momentum after force acts p
2
=m×v=10×8=80kg.m/s
c) Gain in momentum per second =
2
40
=20kg.m/s
d) Acceleration a=
t
v−u
=
2
8−4
=2m/s
2
Force =m×a=10×2=20 N
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