Question

When a force is applied on a body of mass 10 kg for a period of 48, the velocity of the
changes from 6 m/s to 8 m/s.
a) What is the rate of change of momentum of the body?​

Answer 1

Answer:

plz mark brainlist

Explanation:

Mass of the body =10 kg

Initial velocity u=4 m/s

Final velocity v=8 m/s

Time t=2s

a) Momentum before force acts p

1

=m×u=10×4=40kg.m/s

b) Momentum after force acts p

2

=m×v=10×8=80kg.m/s

c) Gain in momentum per second =

2

40

=20kg.m/s

d) Acceleration a=

t

v−u

=

2

8−4

=2m/s

2

Force =m×a=10×2=20 N