Question

when a force of 1.6×10-16N act on an electron of charge 1.6×10^-19 C the electric field intensity is​

Answer 1

Answer:

Correct option is

C

1.28×10  

−13

N,1.2×10  

−4

m

The force acting on electron

F=q(v×B)

=1.6×10  

−19

(4×10  

6

×2×10  

−1

)

=1.28×10  

−13

N

Also, F=  

r

mv  

2

 

​

 

r=  

F

mv  

2

 

​

=  

1.28×10  

−13

 

9×10  

−31

×(4×10  

6

)  

2

 

​

 

=1.2×10  

−4

 m