Question

when a force of 150N is applied to a body ,it is displaced by 15m making an angle of 60° with the force .Find out the work done by the force??​

Answer 1

ㅤㅤGiven:-

Force applied on the body is (F= 150 N )and it displaced by ( s = 15 m) making an angle 60°.

ㅤㅤTo find :-

Work done by the body

Solution:-

ㅤㅤㅤㅤWork done by the body is given by .

$\underline{ \boxed{ \sf \: W = FS\: cos \theta}}$

where,

W = workdone

F = force applied

S = Displacement

ㅤㅤㅤㅤㅤ¤ Substituting the values,

$\implies \sf \: W = 150 \times 15 \times cos60 {}^{ \circ}$

$\implies \sf \: W = 150 \times 15 \times \dfrac{1}{2}$

$\implies \sf \: W = 75 \times 15$

$\implies \sf \: W = 1125 \: J$

So, work done by the body is 1125 J

ㅤㅤㅤKnow more :-

•Usually work can be expressed in joules (J).

•Work done by the body may be the Potential energy, Kinetic energy, Elastic potential energy etc ..

• Energy and work have same units.

Answer 2

Answer:

Force applied on the body is (F= 150 N )and it displaced by ( s = 15 m) making an angle 60°.

ㅤㅤTo find :-

Work done by the body

Solution:-

ㅤㅤㅤㅤWork done by the body is given by .

\underline{ \boxed{ \sf \: W = FS\: cos \theta}}

W=FScosθ

where,

W = workdone

F = force applied

S = Displacement

ㅤㅤㅤㅤㅤ¤ Substituting the values,

\implies \sf \: W = 150 \times 15 \times cos60 {}^{ \circ}⟹W=150×15×cos60

∘

\implies \sf \: W = 150 \times 15 \times \dfrac{1}{2}⟹W=150×15×

2

1

Explanation:

Force applied on the body is (F= 150 N )and it displaced by ( s = 15 m) making an angle 60°.

ㅤㅤTo find :-

Work done by the body

Solution:-

ㅤㅤㅤㅤWork done by the body is given by .

\underline{ \boxed{ \sf \: W = FS\: cos \theta}}

W=FScosθ

where,

W = workdone

F = force applied

S = Displacement

ㅤㅤㅤㅤㅤ¤ Substituting the values,

\implies \sf \: W = 150 \times 15 \times cos60 {}^{ \circ}⟹W=150×15×cos60

∘

\implies \sf \: W = 150 \times 15 \times \dfrac{1}{2}⟹W=150×15×

2

1