Question

When a force of 50 N acts on a body, the body is displaced through a distance of 3 min

a direction normal to the direction of the force. The work done by the force

Ans:- Zero​

Answer 1

Answer:

• 0 J is the required work done by the force

Explanation:

According to the Question

It is given that,

• Force ,F = 50N
• Distance ,s = 3m
• Angle ,θ = 90°

we have to calculate the work done by the force .

As it is given that the direction of force is normal .

• Work Done = FsCosθ

On substituting the value we get

↠ Work Done = 50 × 3 × Cos90°

↠ Work Done = 150 × 0

↠ Work Done = 0 J

• Hence, the work done by the force is 0 .

Answer 2

CONCEPT :-

• in order to solve this question we need to understand force and work done. Force is defined as push or pull on an object which causes the state change of the object, either bringing it to rest or in motion. Work done is defined as the amount of force in a direction of displacement of an object that causes a unit displacement in an object. By doing work, energy is being stored in an object in the form of potential or kinetic energy.

QUESTION :-

• When a force of 50 N acts on a body, the body is displaced through a distance of 3 min a direction normal to the direction of the force. The work done by the force

GIVEN :-

• force of 50 N acts on a body,

• distance of 3 min

TO FIND :-

• work done by the force = ?

SOLUTION :-

work done by the force = 50 × 3 × cos 90°

then, we will multiply 50 with 3 we get :-

done work by the force = 150 × 0

we will multiply 150 with 0 we get :-

done work by the force = 0

The work done by the force = 0