Question

When a force of 500 dyne moves a body through 20 cm, the work done by force is equal to​

Answer 1

Given:

A force of 500 dyne moves a body through 20 cm.

To find:

Work done by the force ?

Calculation:

Since the force is directed along the direction of displacement, the net work done can be calculated by multiplying the force with the displacement of the object.

$\sf \therefore \: work = force \times displacement$

$\sf \implies \: work = 500 \: dyne \times 20 \: cm$

$\sf \implies \: work = (500 \times {10}^{ - 5} \: N)\times (20 \times {10}^{ - 2} \: m)$

$\sf \implies \: work = 500 \times {10}^{ - 5} \times 20 \times {10}^{ - 2 } \: Nm$

$\sf \implies \: work = 1000 \times {10}^{ - 7} \: Nm$

$\sf \implies \: work ={10}^{ - 4} \: Nm$

$\sf \implies \: work ={10}^{ - 4} \: joule$

So, work done is 10^(-4) Joules.