Question

when a force of 500dyne moves a body through 20cm the work done by force is equal to??
a.10 raise to power -3J
b.10 raise to power -5J
c.10 raise to power 5J
d.10 raise to power 3J​

Answer 1

Explanation:

Given:-

• Force ,F = 500 dyne = 500/100000 = 0.005 N

• Displacement ,s = 20cm = 20/100 = 0.2 m

To Find:-

• Work Done

Solution:-

As we know that work done is calculated by the product of force and displacemet.

• W = Fs

where,

W is the Work Done

F is the Force

s is the Displacement

substitute the value we get

→ W = 0.005 × 0.2

→ W = 0.001 J

→ W = 10⁻³ J

• Therefore, the work done by the body is 10⁻³ Joules.

Hence, the required Option is (a) 10 raise to the power of -3 Joules.

Answer 2

Answer:

Given :-

• Force = 500 Dyne
• Displacement = 20 cm

To Find :-

Work done

Solution :-

Firstly we will convert

$\huge \tt Dyne \longrightarrow Newton$

$\tt \dfrac{500}{100000} \: = 0.005 \: n$

$\huge \tt \: CM \longrightarrow M$

$\tt \dfrac{20}{100} \: = 0.2 \: m$

Now,

Let's find Work done

$\huge \tt \: W = Fs$

Here,

W = Work done

F = Force applied

S = Displacement

$\tt \: W = \: 0.005 \times 2$

$\tt \: W = 0.001 \: J$

Therefore :-

Correct Option (A)