When a force of 50N is applied along the length of a 10 m long wire, the
stress produced in the wire is 5×10⁸ N/m²Find the area of cross section of
the wire
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Answer:
10^-7 m^2
Explanation:
Given, F= 50 N
Stress = 5×10^8 N/m^2
A=?
We know that, Stress= F/A
A = F/ stress
= 50/5×10^8
=10 × 10^-8
= 10^-7 m^2
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