Question

When a force of 60n is applied on block of mass 20kg the static friction between the block and surface is 0.8 find the frictional force acting between the block and surface is

Answer 1

${\tt{\pink{ANSWER}}}$

f = 60N

${\tt{\pink{\underline{\underline{Explanation}}}}}$

$F_{ext} \: = 60 \: N$

${\mu}_{s} \: = 0.8$

mass = 20 kg

N = 200N

$f_{l} \: = {\mu}_{s} \: \times N$

$f_{l} \: = 160 \: N$

$as \: f_{l} \: > F_{ext} \\ so \: \\ friction \: = F_{applied}$

friction = 60N