Question

When a force with a force of 4 Kg is thrown vertically upwards, it achieves a maximum height of four meters. Find the force exerted by the force of gravity on it during the position in this upward direction. (G = 10 ms 1)​

Answer 1

Answer:

I think answer is 128

force

Answer 2

u = 40 m/s

As the stone is thrown upward the acceleration due to gravity is to be taken negative.

g = - 10 m/s2

v2 - u2 = 2

For

we can write this eq

v2 - u2 =2gh

the stone reaches the maximum height its final velocity v =0

Thus,

0 - (40)2 = 2× (-10) × h

- 1600 = -20 × h

h = 80 m

So, the maximum height to which the stone can reach is 80 m.

The total distance covered by the stone = 80 + 80 = 160 m

And stone back to its initial position the displacement of the stone = 0