Physics, asked by hitheshvarma7428, 11 months ago

When a galvanometer is shunted by resostance s its current?

Answers

Answered by Anonymous
36

Answer:

Using the relation

S=G(n−1)

⇒G=S(n−1)

and S′=G(n′−1)

⇒n′=G+S′S′

∴n′=S(n−1)+S′S′

Answered by ItsDynamoGirl
4

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 s(n - 1) +  {s}^{1}    \\  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  1

Q. When a galvanometer is shunted by resistance S, its current capacity increases n times. lf the same galvanometer is shunted by another resistance S', its current capacity will increase by n'is given by

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