Question

When a galvanometer is shunted with a 4ω resistance, the deflection is reduced to one-fifth. If the galvanometer is further shunted with is further sh?

Answer 1

When shunted with resistance 4 ohm,

I/5×Rg=4I/5×4(Initial current is I)

So,

Rg=16 ohm

When further shunted with 2 ohm resistance,

I'×16=(I−I')×4/3

Or 

I'=I/13

Further reduction in current=I/5−I/13=8/13(I/5)

Thus, further reduction in deflection is 8/13 of the deflection when shunted with 4 ohm resistance only.

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Answer 2

I/5×Rg=4I/5×4(Initial current is I)

So,

Rg=16 ohm


I'×16=(I−I')×4/3

Or 

I'=I/13

Further reduction in current=I/5−I/13=8/13(I/5)


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