Question

When a galvanometer with a shunt is joined in an electrical circuit 2% of the total current passes through the galvanometer. Resistance of galvanometer is G. Find the value of shunt.

Answer 1

Answer:

galvanometer with a shunt is joined in an electrical circuit 2% of the total current passes through the galvanometer

Answer 2

Answer:

$Resistance\ of\ shunt\ =\ \dfrac{G}{49}$

Explanation:

Let's consider total current be I  and resistance of shunt is R.

It is given that only 2% of current is passing through the galvanometer, so the rest current will pass through the shunt. So, the current passing through the shunt will be 98% of total current.

Now, according to ohm's law,

Voltage = current x resistance

so, voltage across galvanometer,

$V_1\ =\ 0.02I\times G$

and voltage across shunt,

$V_2\ =\ 0.98I\times R$

Since, both are connected in shunt so voltage across them will be equal.

So,

$V_1\ =\ V_2$

$=>\ \ 0.02I\times G\ =\ 0.98I\times R$

$=>\ R\ =\ \dfrac{G}{49}$

So, the resistance of the shunt will be $\dfrac{G}{49}.$