Question

When a glass rod is rubbed with a piece of silk it acquires +10 micro coulomb of charge. How many electrons have been transferred from glass to silk?

Answer 1

Answer:

$5.26\times 10^{13}\ \rm electrons$.

Explanation:

According to Quantisation of Charge, the charge transfers from one body to another body is given by

$Q = \pm ne$.

where,

• $Q$ = total charge transferred.

• $e$ = amount of charge on a single electron = $1.6\times 10^{-19}\ C$.

• $n$ = number of electrons transferred.

Given:

$Q=+10\ \mu C = +10\times 10^{-6}\ C$.

Therefore,

$10\times 10^{-6} = n\cdot 1.6\times 10^{-19}\\n = \dfrac{10\times 10^{-6}}{1.6\times 10^{-19}}\\=5.26\times 10^{13}\ \rm electrons.$

Answer 2

Answer:

5.26×10

13

electrons .

Explanation:

According to Quantisation of Charge, the charge transfers from one body to another body is given by

Q = \pm neQ=±ne .

where,

QQ = total charge transferred.

ee = amount of charge on a single electron = 1.6\times 10^{-19}\ C1.6×10

−19

C .

nn = number of electrons transferred.

Given:

Q=+10\ \mu C = +10\times 10^{-6}\ CQ=+10 μC=+10×10

−6

C .

Therefore,

\begin{gathered}10\times 10^{-6} = n\cdot 1.6\times 10^{-19}\\n = \dfrac{10\times 10^{-6}}{1.6\times 10^{-19}}\\=5.26\times 10^{13}\ \rm electrons.\end{gathered}

10×10

−6

=n⋅1.6×10

−19

n=

1.6×10

−19

10×10

−6

=5.26×10

13

electron