Math, asked by nikhilreddymanda, 19 days ago

When a heap of pebbles is arranged into groups having 8 pebbles each, 2 pebbles are left. If they arranged into groups having 10 pebbles each, 4 pebbles are left and when they are arranged into groups having 12 pebbles each, 6 pebbles are left. Find the least number of pebbles in the heap.

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Answers

Answered by vlone2153
0

Answer:

108

Step-by-step explanation:

  1. 2 \times 6 \times 4 = 48 \\ 60 + 48 = 108
Answered by harshithsaivemula14
3

Answer:

C] 114

Step-by-step explanation:

verification method

A] 108 when divided by 8 gives 4 as remainder . [so this option is wrong ]

B] 126 when divided by 8 gives remainder as 6 . [ so this option is also wrong.]

C] 114 when divided by 8 gives remainder as 2 .

    114 when divided by 10 gives remainder as 4 .

    114 when divided by 12 gives remainder as 6 . [ so this option is correct . ]

D] 102 when divided by 8 gives 6 as remainder . [so this option is wrong. ]

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