Question

When a high resistance voltmeter is connected directly across a resister its reading is 2 V.

An electric cell is sending the current of 0.4 A, (measured by an ammeter) in the electric

circuit in which a rheostat is also connected to vary the current.

(a) Draw an equivalent labelled circuit for the given data.

(b) Find the resistance of the resister.

(c) Name and state the law applicable in the given case. A graph is drawn between a set of

values of potential difference (V) across the resister and current (I) flowing through it.

Show the nature of graph thus obtained.

please don't send fake answer ​

Answer 1

Answer:

Answer

Since the voltmeter reading shows 2 V. Thus V=2.

Also, Current send by electric cell =0.4 A

Thus I=0.4 A

By Ohm's law V=IR

⇒2=0.4×R

⇒R= 0.4

2 = 4

20 =5 Ω

Answer 2

Answer:

$\huge{\textbf{{{\color{navy}{Ꭺŋ}}{\red{ѕw}}{\pink{єr♤࿐}}{\color{pink}{:}}}}}$

$\bf\huge{\purple{╔════════♡︎═╗}}$

Since the voltmeter reading shows 2 V. Thus V=2. 

Also, Current send by electric cell =0.4 A

Thus I=0.4 A

By Ohm's law V=IR

⇒2=0.4×R

⇒R=0.42=420=5 Ω

The resistance of the resistor is 5 Ω.

$\bf\huge{\pink{╚═♡︎════════╝}}$