Question

When a horizontal force p acts on a cart of mass 20 kg.it moves with a uniform velocity on a horizontal floor.when a force of 1.2 p acts the cart it moves with the acceleration of 0.05 m/seci.then the value of p is?

Answer 1

when a force of p is acting the 20kg box is moving with uniform velocity, that is it's in equilibrium.
now force required to disrupt or disturb it's equilibrium is 1.2p - p
0.2p = ma
m= 20kg and a is 5/100 m/sec sq
p = (20*5)/(100*0.2)
p=5

Answer 2

heya answer is here....