When a horizontal force P acts on a cart of mass 2kg, it moves with a uniform acceleration on a horizontal floor. When a force of 1.2P acts on the cart, it moves with an acceleration of 0.05m/s^2. Find the value of P
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Given :-
When a horizontal force P acts on a cart of mass 20 kg,it moves with a uniform velocity on a horizontal floor. When a force of 1.2P acts on the cart, it moves with an acceleration of 0.05 metre per second square. Find the value of P.
Solution :-
- Since in the first case the body moves with a uniform velocity , the resultant force on it in the horizontal direction must be zero .
H + force of friction = 0
or , force of friction = -H.
- In the second case , the net horizontal force is ( 1.5 H - H ) = 0.5H.
Applying Newton's second law ,
→ F = ma
→ 0.5 H = 50 kg × 0.1 m/s²
→ H = ( 50 kg × 0.1 m/s² ) / 0.5 = 10 N .
Thank You !
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