When a hydrogen atom absorbs an energy of 10.2 ev the change in its angular momentum is
Answers
Answered by
0
Given When a hydrogen atom absorbs an energy of 10.2 ev the change in its angular momentum is
Now after absorbing 10.2 ev of energy, the electron goes to its first excited state that is n = 2 from ground state n = 1
Thus change in angular momentum is
L = n h / 2 π
= 6.6 x 10^-34 / 2 x 3.14 where h is planck's constant
L = 1.05 x 10^-34 J S
So orbital angular momentum of electron in hydrogen atom in nth state is given by 1.05 x 10^-34 J s
Similar questions