When a hydrogen atom emits a photon in
going from n = 5 to n = 1, its recoil speed is
almost
a) 104 m/s
b) 2 x 10-2 m/s
c) 4 m/s
d) 8 10 m/s
Answers
Answered by
1
Energy of photon emitted =13.6(
1
1
−
25
1
)eV=13.056 eV
Now, momentum of the photon =
3×10
8
13.056×1.6×10
19
----------(1)
Momentum of the hydrogen = same as (1)
Let recoil speed be V.
V(1841×9.1×10
−31
)=
3×10
8
13.056×1.6×10
19
⇒V≈4 m/s
1
1
−
25
1
)eV=13.056 eV
Now, momentum of the photon =
3×10
8
13.056×1.6×10
19
----------(1)
Momentum of the hydrogen = same as (1)
Let recoil speed be V.
V(1841×9.1×10
−31
)=
3×10
8
13.056×1.6×10
19
⇒V≈4 m/s
Answered by
0
Answer:
4 m/s is the answer....
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