Chemistry, asked by pavibluish3050, 1 year ago

When a hydrogen atom emits a photon of energy 12.1eV, the orbital angular momentum changes by

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Answered by ramcharan54
0

Emission of photon of 12.1eV corresponds to the transition from n=3 to n=1

∴ Change in angular momentum

=(n2−n1)h2π

=(3−1)h2π

=hπ

=6.626×10−343.14

=2.11×10−34JSec

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