When A increases by 18% then B increases by 16%, And when B increases by 18% Then C increases by 9% A is increased from to 4. C must therefore increase from 80 to:
Answers
Answer:
36
Step-by-step explanation:
because A is increases 6
so C must
increase by 6
so I chooses 36
Given:
When A increases by 18% B increases by 16%, When B increases by 18% then C increases by 9%.
To Find:
If A is increases from 32 to 48, C is increased from 80 to which value?
Solution:
1. It is given that if A is increased by 18% then B increases by 16%,
=> If A increases by 1% then B increases by (16/18)%.
2. It is given that if C is increased by 9% then B increases by 18%,
=> If C increases by 1% then B increases by 2%,
3. If B increases by 1% then, A increases by (18/16)%,
=> If B increases by 2 %, A increases by (9/4)%,
=> If C increases by 1 % then, A is increased by (9/4)%.
4. It is given that A is increased from 32 to 48, The value is increased by 50%,
=> If A is increases by 1% then C is increased by (4/9)%,
=> If A is increased by 50% then C is increased by (200/9)%,
=> The value of C is increased by 22.22%,
=> Final value of C = 80+ 22.22% of 80,
=> Final value of C = 97.77.
Therefore, the value of C increases to 97.77.