Question

When A increases by 18% then B increases by 16%, And when B increases by 18% Then C increases by 9% A is increased from to 32 to 48. C must therefore increase from 80 to:​

Answer 1

Answer:

Let C increase by 1% .

Then , B increase by 2% .

And thus , A increases by ( 18 / 16 ) * 2 = 9 / 4 %

Thus , we conclude that when C increases by 1% , then A increases by 9 / 4 % .

Now , A increases to 32 to 48 ,

Hence , Percent Increase in A = ( 16 / 32 ) * 100

= 50%

Hence , from equation 1 , we have ;

Percent Increase in C = ( 50 ) * 4 / 9

= 200 / 9%

Answer 2

97.8

Step-by-step explanation:

As A increases from 32 to 48

considering 32 as 100% and then 48 is 150%

now the A is increased by 50% so B must be increased by 44.44%

As the B increased the C will increase by 22.22%

Let us consider 100% = 80

then for 122.2% = ?

==> 97.8

Hence the C increases from 80  to 97.8