When a large pipe and a small pipe are opened for 4 hours and 9 hours respectively, a tank is half filled. but when both pipes are opened simultaneously the tank is filled in 12 hours. how many hours does the larger pipe take to fill the tank?
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Part of the tank filled by the large pipe in 1 hr = x
Part of the tank filled by the small pipe in 1 hr = y
Part of the tank filled by the large pipe and small pipe in 1 hr = 1/12
=> x + y = 1/12 ------(1)
Part of the tank filled by the large pipe in 4 hr + Part of the tank filled by the small pipe in 9 hr = 1/2
=> 4x + 9y = 1/2 ----(2)
Solve (1) and (2) for x
(1)×9 - (2) => 5x = 9/12 - 1/2
5x = 1/4
x = 1/20
i.e., part of the tank filled by the large pipe in 1 hr = 1/20
=> large pipe alone needs 20 hours to fill the tank
Part of the tank filled by the small pipe in 1 hr = y
Part of the tank filled by the large pipe and small pipe in 1 hr = 1/12
=> x + y = 1/12 ------(1)
Part of the tank filled by the large pipe in 4 hr + Part of the tank filled by the small pipe in 9 hr = 1/2
=> 4x + 9y = 1/2 ----(2)
Solve (1) and (2) for x
(1)×9 - (2) => 5x = 9/12 - 1/2
5x = 1/4
x = 1/20
i.e., part of the tank filled by the large pipe in 1 hr = 1/20
=> large pipe alone needs 20 hours to fill the tank
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A lens with one convex and one concave side is convex-concave or meniscus. It is this type of lens that is most commonly used in corrective lenses. If the lens is biconvex or plano-convex, a collimated beam of light passing through the lens converges to a spot (a focus) behind the lens.
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