When a lift is moving upward with acceleration of 5 m/s2 then percentage change in the weight of the personin the lift is x%. If the lift is moving down with acceleration 5 m/s2 then percentage change in the weight ofsame person is y%. Then the ratioyx is (g = 10 m/s2)
Answers
Answer:
y ratio x is 1:1
Explanation:
Let the mass of the person be m
When a person is inside the lift and the lift is moving up with an acceleration a m/s² then the person will feel her weight increase by ma.
Therefore net weight is
W = m(g + a)
When a person is inside the lift and the lift is going down with an acceleration a m/s² then the person will feel her weight decrease by ma.
Therefore net weight is
W' = m(g - a)
Here, a = 5 m/s²
Change in the weight of the person when the lift is moving up
= m(g + a) - mg = ma
Percentage change in the weight of the person when the lift is moving up
x = (ma/mg) × 100 = 100a/g .............. (1)
Similarly percentage change in the weight of the person when the lift is moving down
y = (ma/mg) × 100 = 100a/g .............. (2)
From equation (1) and (2)
x = y
or, y:x = 1:1