Question

when a lift moves down with acceralation then​

Answer 1

Answer:

When elevator is accelerating downwards with acceleration a, then mg-R= ma or R= m (g-a). Thus the apparent weight of the man becomes less than the actual weight, when elevator is accelerating downwards. If a= g, then R = m (g-g) =0.

Answer 2

Answer:

When elevator is accelerating downwards with acceleration a, then mg-R= ma or R= m (g-a). Thus the apparent weight of the man becomes less than the actual weight, when elevator is accelerating downwards. If a= g, then R = m (g-g) =0.