Question

when a liquid in a glass vessel is heated its Apparent expansion is 10.3 into 10 ^ -4 degrees celsius same liquid when heated in a metal is Apparent expansion is 10.06 into 10 ^ -4 degrees celsius the coefficient of linear expansion of the metal is if Alpha of Glass is equal to 9 into 10 ^ - 6 Celsius ​

Answer 1

Hey Dear,

◆ Answer -

α(metal) = 8.79×10^-6 /℃

◆ Explanation -

Let ∆Vg and ∆Vm be the apparent expansion of same liquid in glass and metal vessel respectively by same change in temperature.

Alpha for glass -

αg = (∆Vg/V) / ∆T

αg = ∆Vg / V.∆T

Alpha for metal,

αm = (∆Vm/V) / ∆T

αm = ∆Vm / V.∆T

Dividing αm by αg,

αm / αg = (∆Vm / V.∆T) / (∆Vg / V.∆T)

αm / αg = ∆Vm / ∆Vg

αm = αg × ∆Vm / ∆Vg

αm = 9×10^-6 × 10.06×10^-4 / 10.3×10^-4

αm = 8.79×10^-6 /℃

Therefore, alpha for metal is 8.79×10^-6 /℃.

Thanks dear...