Question

when a load 10kg is hung from the wire ,then extension of 2m is produced .Then work done by restoring force is

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Answer 1

Answer:

98 joule

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Answer 2

Answer:

w = 1 /2kx^2

(mg = kx )

k = mg /x = 10 x 10 /2

= 50

w = 1 /2 kx^2

= 1 /2 x 50 x 4

= 100 J

correct answer

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