Physics, asked by Sajid1111, 1 year ago

when a load of 10 kg is hung from the vire then extension of 2m is produced. tha work done by restating force is

Answers

Answered by 8055SAHIL
2
work done =force*extension
=10*10×2=200
if answer is correct hit the thank you
Answered by singhjogi1969
1

work done = 1/2 × force × extension

= 1/2 × (10 × 10) × 2

= 1/2 × 100 × 2

work done = 100 J

{ I've taken g = 10m/s²}

hope this answer will be helpful to you.

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