Question

When a load of 10kg is suspended on a metallic wire its length increased by 2mm . The force constant of the wire is

Answer 1

Given in the question :-

mass = 10 kg

Increase in length = 2 mm .

Force constant , k = ?

We know the formula ,

F = k ( l₂ - l₁ )

mg = k ( l₂ - l₁ )

k = ( 10 × 9.8 ) / 2 × 10⁻³

k = 98/ 2 × 10⁻³

k = 49000 Nm⁻¹

Hence the force constant of the wire is 49000 Nm⁻¹ .

Hope it Helps.

Answer 2

Answer:

5×10^4N/m

Explanation:

we know

f=kx(restoring force)

where f is force

k is force constant

x is the elongation

,f = kx

mg=kx

10×10=k×2/1000

100×1000/2=k

k=50×10^3

k=5×10^4