Question

when a load of 1kg is hung from the wire , a extension of 2mm is produces.then the energy stored on the rod is ? a)10mJ b)20mJ c)25mJ d)5mJ​

Answer 1

Answer:

20mJ

Explanation:

Apply, Energy stored = mgh

where, m = Mass

g = Gravitational constant

h = Extension produced

So, E = 1 × 10 × 2 × (10^-3)

= 2× 10^-2

= 20 mJ (ans.)

hope this will help you.

Answer 2

Given,

Mass of the load=1kg

Extension produces=2mm

To Find,

Energy stored on the road.

Solution,

Energy stored on the rod will  = mgh

where, m = Mass

g = Acceleration due to gravity

h = Extension produced

So, E = 1 × 10 × 2 × (10^-3)

       = 2× 10^-2

      = 20 mJ

Hence, the energy stored in the rod is 20mJ(Option B).