when a load of 5kg is hung on a wire an extension of 3m takes place the work done will be
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Answered by
3
Explanation:
we know that
w = fd
f = 10 kg
d = 3m
w = 3×10kgm
30kgm or 30 joules
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jay272
Answered by
3
Answer:147 j
work done=potential energy
w=mgh
w=5×9.8×3
w=147j
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