Question

When a local train travels at a speed of 60 kmph, it reaches the destination on time. When the same train travels at a speed of 50 kmph, it reaches its destination 15 minutes late. What is the length of the journey?

Answer 1

as the distance is same for both trains
1st train distance=60×time
2nd train distance =50×(time+15)
60×t=50(t+15)
on equating we get
time =75mins
so distance=75×60=4500km
hope it helps you!

Answer 2

Answer:

The length of the journey will be 75Km if the train travels at 60 kmph or 50Kmph

Explanation:

Let the time taken by a train to reach destination at 60kmph is x

While travelling with the speed of 60 kmph the train reaches destination on time. If train travels at 50 kmph it reaches late by 15 minutes

Thus, the time taken by the train with the speed of 50 kmph will be = (x+15)

We know, Distance = speed × Time

The train is covering equal distance whether the speed is same or not, Let the distance travelled by the speed of 60 kmph will be d1 and the distance travelled by 50 kmph speed is d2.

d1 = d2

60 × x = 50 × (x+15)

60x = 50x + 750

60x - 50x = 750

10x = 750

x = $\frac{750}{10}$

x = 75Km

Therefore, the length of the journey will be 75km

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