Question

When a magnetic dipole of moment M rotates freely about its axis from unstable
Equilibrium to stable equilibrium in a magnetic field B the rotational kinetic energy
Gained by it is​

Answer 1

Answer:

Kinetic energy gained by magnetic dipole is 2MB

Explanation:

As we know that magnetic potential energy of a magnetic dipole is given as

$U = - M.B$

$U = - MB cos\theta$

now if magnetic dipole rotate from unstable equilibrium to stable equilibrium then we have

$KE = \Delta U$

$KE = (-MBcos\theta_1) - (-MBcos\theta_2)$

here we know that at unstable equilibrium

$\theta_1 = 180^o$

and at stable equilibrium we have

$\theta_2 = 0^o$

so we have

$KE = (-MBcos180) - (-MBcos0)$

$KE = 2MB$

#Learn

Topic : Magnetic potential energy

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