when a male with heamophilia XhY is crossed with female carrier of both heamophilia and colourblindness XcXh then what is the probability that female offspring will turn out to be phenotypically normal?
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Answer:
50%
Explanation:
XhY x XcXh parents
XhXc XhXh XcY XhY Offsprings
so 1 daughter will be carrier for both hemophilia and colorblindness who will be phenotypically normal.
another daughter is haemophilic
1 son is haemophilic and another is colorblind
so out of 2 daughters 1 is normal hence 50% daughters will be phenotypically normal
hope it helps
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