when a man borrowed Rs 3125 for C.I which amounted to be Rs 4500 in 2 years . what was the per annum
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CI=p(1+r/100)^t
=3125(1+r/100)^2
=3125(100+r÷100)^2
1375÷3125=(100+ r)^2÷(100)^2
0.44÷10000=(100+r)^2
0.000044
=3125(1+r/100)^2
=3125(100+r÷100)^2
1375÷3125=(100+ r)^2÷(100)^2
0.44÷10000=(100+r)^2
0.000044
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