Question

When a man moves down an
inclined plane with a constant
speed 5 m/s which makes an
angle of 37° with the horizontal.
He finds that the rain is falling
vertically downwards. When he
moves up the same inclined plane with the same speed, he finds that the rain makes an angle theta = tan inverse of(7/8) with the horizontal. The speed of the rain is
.
.
pls solve this i will mark brainliest​

Answer 1

Explanation:

Please see the figure to find the axes .

Let the x- component of rain be x and that of y- component be y .

Now , apply the concepts of relative velocity , subtract the x-component of man's velocity from rain 's x-component and same for y-component of rain.

So , man's x-component = 5 *cos37 = 4 m/s , man's y-component = 5 sin37 = - 3 m/s

so , velocity of rain relative to man : x component = x -(4 ) = (x - 4) m/s ; y component = (y +3) m/s

as the velocity seems vertical horizontal component must be zero , so x - 4 =0 , x = 4 m/s

second case , man's x component = - 5 *cos37 = -4 m/s , man's y component = 5 sin37 = 3 m/s

so , velocity of rain relative to man : x component = x -( -4 ) = (x + 4) m/s ; y component = (y -3) m/s

as angle from the horizontal is tan ^-1 (7/8) , ; 7/8 = -( y- 3) / x +4

7/8 = 3-y /8 , therefore , y = -4 m/s , i.e 4m/s downwards .

so velocity of rain is (42 +42 )1/2 = 5.65 m/s 45deg to the vertical.